From the Extra Solar Planets Encylopedia Star M[.sini] Semi-maj. Period Ecc. Inclin. Radius Jup. mass:(J) Axis (AU) years(y) (deg) (Earth Earth mass:(E) days(d) rad.) (note 1) zeta2 Ret 0.27(J) 0.14 18.9 (d) 0. - - 11 pc G1V V = 5.24In a rather strange "about face", the above information was removed from the Extra Solar Planets Encyclopedia site after 4 days .. the official reason was that "the data may have been misinterpreted and there probably is no planet." Fortunately, I had saved the original version of the Encyclopedia with the Zeta 2 Reticuli information still present.
Now this big quarter of a Jupiter mass planet is in an orbit about Zeta 2 Reticuli which lasts 18.9 days and has a semi-major axis of 0.14 Astronomical Units. For comparison Mercury has a semi-major axis of 0.39 Astronomical Units (AU) [1.00 Astronomical Units = the distance of between the earth and the sun, about 93 million miles). Now assuming that this newly discovered planet is the closest one to Zeta 2 Ret (it's hard to imagine a closer one) then following Bode's Law (the law which states each planet is about twice the distance from it's sun as its inner neighbour) Reticulum 2 should be at 0.28 AU, Reticulum 3 should be at 0.56 AU and INTERESTINGLY Reticulum 4 would be at 1.12 AU in between the Earth's 1.00 AU and Mars's 1.52 AU, well within the lifezone of a G class star! Thanks to Joe LeSesne, E-mail : raver187@m-net.arbornet.org
I just found another possible way that this recent discovery could confirm part of Lazar and Jarod 2's story. I found the length of the Zeta 2 Reticulum 4's year. How did I do this you might ask? Simple, with calculator in hand I used two elementary laws of Astronomy. Bode's Law and Kepler's 3rd Law. The numbers I used were from that data on the Extrasolar Planets Encyclopedia Web Site are these: Semi-major axis measured in Astronomical Units, and Period measured in days. The newly discovered planet has a semi-major axis of 0.14 AU and a period of 18.9 days Some Definitions: 1 Astronomical Unit (AU) = 93 million miles, the distance between the Earth and Sun. Semi-major axis is the measurement of the planets orbit in relation to it's star in Astronomical Units. The Earth's semi- major axis is 1.00 AU. Period is the amount of time it takes to complete one orbit, a planet's period is it's year. The Earth's Period is 365.26 days. First, Bode's Law: As I stated before if you apply Bode's law which states: The semi-major axis of each planet is double that of it's neighbour nearer to the star.Or simply each planet is about twice as far from its star as its inner neighbour. i.e. Jupiter is 5.2 AU from the Sun, Saturn is 9.5 AU. Now if you apply this to the new discovery of a planet around Zeta 2 Reticuli and you assume this planet is the closest to its star this making it the closest planet to Zeta Reticuli 2 (Reticulum 1 we will call it in keeping with Lazar's naming convention which I should add differs from the IAU convention which would name it Zeta 2 Reticulum A - so far) At 0.14 AU it's hard to imagine a closer planet to Zeta 2 Ret., for comparison Mercury is at 0.387 AU from the Sun so this newly found planet is Reticulum 1 in all likelyhood. Using Bodes law we can extrapolate where the other planets of Zeta 2 Reticuli should be. Kepler's 3rd law relates the planet's period or year to it's semi- major axis of it's orbit. Mathematically this is expressed as P(squared) = a(cubed). P is the Period measured in earth years and a is the semi-major axis measued in Astronomical units (AU) Using both of these we can find out the length of the year on each hypothetical planet in the Zeta 2 Reticuli system, INCLUDING Reticulum 4, Bob Lazar's home of the Greys. Now lets apply Bodes Law and Kepler's 3rd Law: Planets of the Zeta 2 Reticulum System =============================================================== Planet Semi-Major axis Period(days) Period(years) --------------------------------------------------------------- Reticulum 1 0.14 (AU) 18.9 (days) 0.052 (years) Reticulum 2 0.28 54.0 0.1481 Reticulum 3 0.56 152.9 0.4196 Reticulum 4 1.12 432.6 1.12 --------------------------------------------------------------- So one Reticulum 4 year is equal to roughly 1.12 earth years OR 432 days. And it is in roughly the same position in Zeta 2 Ret's "life-zone" as the Earth is in the Sun's. Zeta 2 Ret is a G1V spectral class star, the sun is a G2V. They are both G class main sequence stars, the difference between the 2 and the 1 indicates that Zeta 2 Reticuli is a little hotter than the sun. The higher the middle number the lower the temperature. The V means they are both main sequence (middle age) stars but given Zeta 2 Reticuli's higher temperature, and lower metallicity, it is probably older than the sun by a couple billion years. So basically the Sun is a little cooler and younger than Zeta 2 Reticuli. For comparison here is a breakdown of the inner planets of our solar system. Planets of the Solar System =============================================================== Planet Semi-Major axis Period(days) Period(years) --------------------------------------------------------------- Mercury 0.387 (AU) 87.97(days) 0.2409(years) Venus 0.723 224.7 0.6152 Earth 1.00 365.26 1.0000 Mars 1.524 686.98 1.8809 --------------------------------------------------------------- So this brings me to my conclusion. We can check part of Lazar and Jarod 2's story by asking the simple question: "How long is a year on Reticulum 4?" If the answer is anywhere in the neighborhood of 410-445 days (I'm allowing a lot for error) then their stock will have gone up even more. Keep me posted as to what you find out. Thanks to Joe LeSesne, E-Mail : raver187@m-net.arbornet.org
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